Kansanto Spring

Kansanto Spring

Which of the following is a term about hot spring is NOT correct?(1 Point) A. Hydrothermal Spring B. Geothermal Spring C. Mineral Spring D. Fountain Spring​

Daftar Isi

1. Which of the following is a term about hot spring is NOT correct?(1 Point) A. Hydrothermal Spring B. Geothermal Spring C. Mineral Spring D. Fountain Spring​


Answer:

B. Geothermal Spring

Explanation:

this is my answers


2. 5. Spring is around the corner.' Using deconstructive analysis what does the word "spring" in the sentence symbolizes? a. Spring symbolizes death. b. Spring symbolizes love. c. Spring symbolizes joy. d. Spring symbolizes rebirth.​


Answer:

B

Explanation:

Love start At growing Flowers trees

Hope help po sa inyu

Answer:

B. Spring symbolizes love.

Explanation:

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3. An ideal spring has a spring constant of 15 N/m. The spring is streched 6 cm. What os the potential energy of the spring?


Answer:

potential spring break at cookie dough ice cream and name is H hyperbole in the sounds of it didn't work out for you please comment trick or treat me like a f f o d i l-I offer ew revolver and bat Ganon armor and name is H hyperbole in the morning and name is H hyperbole in the morning

Explanation:

uuuu I offer ew revolver and I give you a call when I get home from work out for you please comment trick or treat me like a f f o d i l-I offer ew


4. What is the relationship between force applied to a spring and the change of extension of that spring?


Answer:

For a given spring and other elastic objects, the extension is directly proportional to the force applied. For example, if the force is doubled, the extension doubles.

directly proportional

The extension of a spring or other elastic object is directly proportional to the force exerted. When the force is doubled, the extension doubles as well.


5. Spring Give atleast 5 examples of spring force


Answer:

rubber bands, bungee cords, the keys and buttons found on computers, elevators, appliances, toys

Explanation:


6. a spring is connected to a wall as show below. a mass on horizontal surface is connected to the spring and pulled to rightv along the surface stretching the spring by 25cm. If the pulling force exerted on the maa was 80.N determine the spring constant of the spring


Answer:

ZA WARUDO TOKIWO TOMARE

Answer:

Watashi nomae wa tetsutetsudes


7. When a 4.25-kg object is placed on top of a vertical spring, the spring compresses a distance of 2.62 cm. What is the force constant of the spring?


[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The force exerted by a spring is

[tex]\boxed{F = kx}[/tex]

where:

F = force exerted by a spring

k = spring constant

x = distance

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Listing the given values

m = 4.25 kg

d = 2.62 cm = 0.0262 m

Solving for k

[tex]F = kx[/tex]

[tex]\dfrac{F}{x} = \dfrac{kx}{x}[/tex]

[tex]k = \dfrac{F}{x}[/tex]

[tex]k = \dfrac{mg}{x}[/tex]

[tex]k = \dfrac{(\text{4.25 kg})(\text{9.8 m/}\text{s}^{2})}{\text{0.0262 m}}[/tex]

[tex]\boxed{k = \text{1.59 kN/m}}[/tex]

Therefore, the force constant is 1.59 kN/m.

[tex]\\[/tex]

#CarryOnLearning


8. The distance (d) that a spring is stretched is directly proportional to the mass (m) of the object that is stretching the spring. If a mass of 252 grams stretches a spring 14 cm, how far will a 126 gram-mass stretch the spring?


Answer:

d = km

14 = k(252) all over 252

k=18

d= 18(126)

d= 2268

Step-by-step explanation:


9. The group hung four notebooks of the same kind in a spring balance. The spring scale is pulled downward and readings are recorded below.If the spring is pulled 3.5 centimeters, what would be the spring scale reading?​


Answer:

D. 18N

Step-by-step explanation:

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10. a spring has a spring constant of 50 n/m and stretches up to the lenght of 5m, CALCULATE THE ELASTIC POTENTIAL "ENERGY" OF THE SPRING


Answer:

12m is the potential energy of the spring

Explanation:

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11. The force constant of spring A is twice that of spring B. Both springs are compressed by the same amount. The elastic potential energy of spring B is ____ the elastic potential energy stored in spring A. a. half b. equal to c. twice d. four times


[tex]\blue{\boxed{\tt{\colorbox{pink}{b.\: equal \:to}}}}[/tex]


12. 7 En which of the following setups does the spring have elastic potential energy? A stretched spring b. A compressed springc. A balance and flattened spring d A spring in a relaxed equilibrium position​


Explanation:

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Answer:

isko moreno vs alfredy control ur tmper so dont be angry

Explanation:

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13. a 4.0 kg box slides with an initial speed of 3.0m/s towards a spring on a frictionless horizontal surface. When the box hits the spring, the spring compresses by 0.30m. What is the spring constant?


Answer:

1.2

Explanation:

beacuse I multiply 4.0 and 0.30


14. The length that a spring will stretch varies directly as the force applied to the spring. If a force of 10 lb will stretch a spring by 2 in, what force will stretch the same spring by 3 in?


Answer:

15 pounds (lb)

Step-by-step explanation:

Suppose X pounds will stretch aspring by 3 inches Because tension and tensile strength distance is proportional.

To the relationship.

10/2 = x/3

x = 10/2 × 3

× = 15

So the answer is 15 pounds.


15. You have two springs that are identical except that spring 1 is stiffer than spring 2 on which spring is more work done: (a) if they are stretched using the same force; (b) if they are stretched the same distance


Answer:

B they are same distance

16. Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25m with a spring constant k of 200N/m. What is the elastic potential energy stored from the spring’s compression?


Answer:

The elastic potential energy is 6.25 J.

Explanation:

In our case, we are to solve for the elastic potential energy stored on the compressed spring connected between the two carts. Originally, the length of the spring is 0.50 m but when compressed, spring becomes 0.25 m.

For the elastic potential energy , we will use the formula:

Ee = 1/2kx²

where

Ee     is the elastic potential energy, unit is in N·m or Joule (J)

k        is the spring constant, unit is in N/m

x        is the amount stretched or compressed from the spring, unit is in meter

For the given information

k = 200 N/m

x = 0.25 m

Ee = ?

Solving the problem

Let us use the formula for elastic potential energy, then substitute the given information, we have:

Ee = 1/2kx²

Ee = 1/2 (200 N/m)(0.25 m)²

Ee = 6.25 N·m or Joule

Therefore, the elastic potential energy stored on the compressed spring is 6.25 J.

To learn more about this topic, just click on the following links:

Definition of elastic potential energy with example

       https://brainly.ph/question/779642

       https://brainly.ph/question/1631424

#LetsStudy


17. what is the difference between coil spring and leaf spring system?​


Answer:

A leaf spring takes the form of a slender arc-shaped length of spring steel of rectangular cross-section. Coil springs as the name suggests, look exactly like how one imagines a spring to look like. It sits on top of the axle or at the lower control arm and the chassis

Answer:

A leaf spring takes the form of a slender arc-shaped length of spring steel of rectangular cross-section. Coil springs as the name suggests, look exactly like how one imagines a spring to look like. It sits on top of the axle or at the lower control arm and the chassis

Explanation:

hope it'll help


18. A spring has a spring constant of 100 N/m and stretches up to a length of 2 m. Calculate the elastic potential energy of the spring.​


Answer:

EPE = 200 J

Explanation:

EPE = ½kx²

EPE = ½(100 N/m)(2 m)²

EPE = 200 J

#CarryOnLearning


19. A spring is displaced by 5 cm and held in place with a force of 500 N. What is the spring constantof the spring?​.


Answer:k=10000 N/m

Step-by-step explanation:


20. a force of 85 N applied to a spring with a spring constant of 345 N/m. How far back spring compressed?​


Answer:

0.25m

Explanation:

let L be the spring compressed.

L = 85N / 345N

L = 0.25m


21. The force required to stretch a spring is proportional to the elongation. of 24 and stretches a spring 3 mm, find the force required to stretch the spring 2 mm.


Answer:

F = -kx. The proportional constant k is called the spring constant. It is a measure of the spring's stiffness. When a spring is stretched or compressed, so that its length changes by an amount x from its equilibrium length, then it exerts a force F = -kx in a direction towards its equilibrium position.


22. a spring with a spring constant of 70N/m is stretched from 0.10m to a 0.30m what is the spring's elastic potential energy? pls i need it now​


Answer:

K = 200 N/m        x = .05 m

Energy stored in spring = 1/2 kx^2 = 1/2 x 200 x .05 ^2 = 0.25 J

 

m= 0.5 kg

 

PE stored in spring = KE imparted to object

0.25 J = 1/2 x 0.5 kg x v^2            v = sqrt 1 = 1 m/s


23. 1. A compressed spring has 0.28 m and its spring constant is 200 N/m. Calculate the elastic potential energy. 2. The vertical spring is linked to a load of mass 5 N/m which is compressed by 10m. Determine the force constant of the spring if the force exerted on the object is 28 N. Calculate the elastic potential energy stored in the spring. 3. A ball is pushed into a spring-loaded launcher with a force of 20 N, which compresses the spring by 0.08 m. A) What is the spring constant of the spring Find the elastic potential energy (PEs). 4. A spring with a force constant of 5.20 N/m has a vertical length of spring is 3.57 m. Calculate the elastic potential


Answer:

1.A spring with a spring constant of 144 N/m is compressed by a distance of 16.5 cm. How much elastic potential energy is stored in the spring?

2.Energy stored in a spring

Work is done when a spring is extended or compressed . Elastic potential energy is stored in the spring. ...

The elastic potential energy stored can be calculated using the equation:

elastic potential energy = 0.5 × spring constant × (extension) 2

3.Given parameters:

Force = 20N

Compression = 0.08m

Unknown:

Spring constant = ?

Elastic potential energy = ?

Solution:

To solve this problem, we use the expression below:

F = k e

F is the force

k is the spring constant

e is the compression

20 = k x 0.08

k = 250N/m

Elastic potential energy;

EPE = \frac{1}{2}

2

1

k e² = \frac{1}{2}

2

1

x 250 x 0.08²

Elastic potential energy = 0.8

4.Elastic potential energy, E = 3.26 J

Explanation:

It is given that,

Force constant of the spring, k = 5.2 N/m

Relaxed length of the spring, X = 2.45 m

When the mass is attached to the end of the spring, the vertical length of the spring is, x' = 3.57 m

To find,

The elastic potential energy stored in the spring.

Solution,

The extension in the length of the spring is given by :

x=x'-Xx=x

−X

x=3.57\ m-2.45\ mx=3.57 m−2.45 m

x = 1.12 m

The elastic potential energy of the spring is given by :

E=\dfrac{1}{2}kx^2E=

2

1

kx

2

E=\dfrac{1}{2}\times 5.2\times (1.12)^2E=

2

1

×5.2×(1.12)

2

E = 3.26 J

So, the elastic potential energy stored in the spring is 3.26 joules.

Step-by-step explanation:

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pa Brailiest po



Answer:

The stiffer the spring is, the smaller the period T. The greater the mass of the object is, the greater the period


25. Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25m with a spring constant k of 200N/m. What is the elastic potential energy stored from the spring’s compression? (answer with solution)​


Answer:

6.25 J

Explanation:

[tex]E _{e} = 0.5k {x}^{2} [/tex]

[tex] = 0.5(200)(.25)^{2} [/tex]

[tex] = 6.25 \: J \: [/tex]


26. If a spring has a spring costant of 2 N/m and it stretched 0.06m, what is the for of the spring?​


Answer:

the force of the string is 12

Explanation:

welcome for the answer


27. Carlo is pushing the spring with a force of 15.6 N by 5.0 cm. A) What is the force constant of the spring? B) How much force is needed to push the spring with addition of another spring which is 6.0 cm?


Answer:

A. k = -312 N/m

B. F = 34.32 N

Explanation:

A.

GIVEN

x = 5.0cm = 0.05m

F = 15.6N

FORMULA

k = -F/x

SOLUTION

k = -15.6N / 0.05m

k = -312 N/m

B.

GIVEN

x = 5.0cm + 6.0cm = 11cm = 0.11m

k = - 312 N/m

FORMULA

F = -kx

SOLUTION

F = -(-312 N/m)(0.11m)

F = 34.32 N


28. Two carts connected by 0.50 m spring hit a wall, compressing the spring to 0.25 m. if the spring constant k is 200 n/m, what is the elastic potential energy stored from the spring’s compression?


Answer:

222211328939

Explanation:

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29. When a 1 kilogram mass is suspended from a spring, the spring stretches 2 cm. the force constant of the spring is approximately?


Answer:

Z -- 500 NEWTONS PER METER


30. what size of spring nature springBottle​


Answer:

NATURE'S SPRING pH9 Drinking Water is available in 350mL, 500mL, 1L, 1.5L, 4L, 6.6L and 10L.

Answer:

NATURE'S SPRING pH9 Drinking Water is available in 350mL, 500mL, 1L, 1.5L, 4L, 6.6L and 10L.

Step-by-step explanation:  

Nature's Spring Purified Drinking Water is a quality yet affordable brand for daily consumption of clean and safe bottled water.


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